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Examples of Ionic Compounds

The [TiNCS6...

Question

The $[T i (N C S)_{6}]^{3 -}$ ion exhibits a single absorption band at $544 n m$ . If the crystal field splitting energy is $21979 \times 10^{- x} k J . m o l^{- 1}$ , then find the value of x.

x = 1

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x = 2

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x = 3

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x = 4

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Solution

The correct option is C $x = 2$
$Δ E = \frac{h c}{λ}$

$= \frac{6.62 \times 10^{- 34} \times 3 \times 10^{8}}{544 \times 10^{- 9}}$

$= 3.65 \times 10^{- 19} J$ per ion
$= 3.65 \times 10^{- 19} \times 6.02 \times 10^{23} J$ $m o l^{- 1}$

$= 219.79 k J$ $m o l^{- 1}$

$= 21979 \times 10^{- 2} k J . m o l^{- 1}$

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Similar questions

{[T i (N C S)_{6}]}_{6}^{3 -}

({in kJmol}^{- 1})

(h = 6.626 \times 10^{- 34} J s; c = 3.0 \times 10^{8} m / s; N_{A} = 6.02 \times 10^{23} ions/mole)

[T i (N C S)_{6}]^{3 -}

(h = 6.626 \times 10^{- 34} J s; c = 3 \times 10^{8} m / s; N_{A} = 6.02 \times 10^{23} i o n s / m o l e)

[T i (N C S)_{6}]^{3 -}

k J m o l^{- 1})

h = 6.6 \times 10^{- 34} J s; c = 3.0 \times 10^{8} m / s; N_{A} = 6.0 \times 10^{23} i o n s / m o l e

[T i (N C S)_{6}]^{3 -}

(i n k J m o l^{- 1})

(h = 6.626 \times 10^{- 34} J . s; C = 3.0 \times 10^{8} m / s; N_{A} = 6.02 \times 10^{23} i o n s / m o l e

[T i (N C S)_{6}]^{3 -}

544 n m

(Planck constant = 6.626 \times 10^{- 34} J s)

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