The time constant in an L-R circuit is that time in which the value of current in the circuit becomes :

I_{0}

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\frac{I_{0}}{2}

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63%

I_{0}

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37%

I_{0}

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Solution

The correct option is C 63% $I_{0}$
current in RL circuit with time is given by,
$i = i_{o} (1 - e^{\frac{- t}{τ}})$
and one time constant is current when $t = τ$ , i.e
$i = i_{o} (1 - e^{- 1})$
which is $0.63 i_{o}$ .

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Similar questions

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The time constant in an L-R circuit is that time in which the value of current in the circuit becomes :

The correct option is C 63% I0current in RL circuit with time is given by,i=io(1−e−tτ)and one time constant is current when t=τ, i.ei=io(1−e−1)which is 0.63io.

The correct option is C 63% $I_{0}$
current in RL circuit with time is given by,
$i = i_{o} (1 - e^{\frac{- t}{τ}})$
and one time constant is current when $t = τ$ , i.e
$i = i_{o} (1 - e^{- 1})$
which is $0.63 i_{o}$ .