The time dependence of the position of a particle of mass m=2 is given by →r(t)=2t^i−3t2^j. Its angular momentum, with respect to the origin, at time t=2 is :
A
36^k
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
−34(^k−^i)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
−48^k
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
48(^i×^j)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is C−48^k Given:
mass m=2
time t=2 →r=2t^i−3t2^j
Now, Position at time t=2 →r(at t=2)=(2×2)^i−(3×22)^j=4^i−12^j
Velocity, →v=d→rdt=ddt(2t^i−3t2^j)=2^i−6t^j