The time in seconds required to produce a potential difference of 20V across a capacitor of 1000μF when it is charged at the steady rate of 200μC/sec is :
A
50
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
100
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
150
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
200
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is B100 Given, C=1000μF V=20V Q=CV Q=1000×10−6×20 Q=2×10−2C ∴ total change required =2×10−2C rate of charging =200×10−6C/s ∴time=2×10−2200×10−6 =100s