The electron in hydrogen atom makes a transition from $n = n_{1} to n = n_{2}$ state. The time period of the electron in the initial state is eight times that in the final state. The possible values are

Q. The electron in a hydrogen atom makes a transition from

n_{1}

n_{2}

state. The time period of electron in

n_{1}

8

times in

n_{2}

. The possible values of

n_{1}

and

n_{2}

are

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The time period for revolution of Bohr electron in an orbit of ground state(n1) is T1 of time period for revolution of electron in higher orbit(n2) is T2. Which values of n1 and n2 are not correct if T1T2=18?

The correct option is C n1=2,n2=3As we know,T∝n3∴T2T1=(n2n1)3=8∴n2n1=2and among given optionsn2/n1=2/1=4/2=6/3=2

The time period for revolution of Bohr electron in an orbit of ground state $(n_{1})$ is $T_{1}$ of time period for revolution of electron in higher orbit $(n_{2})$ is $T_{2}$ . Which values of $n_{1}$ and $n_{2}$ are not correct if $\frac{T_{1}}{T_{2}} = \frac{1}{8}$ ?

The correct option is C $n_{1} = 2, n_{2} = 3$
As we know,
$T \propto n^{3}$
$∴ \frac{T_{2}}{T_{1}} = {(\frac{n_{2}}{n_{1}})}^{3} = 8$
$∴ \frac{n_{2}}{n_{1}} = 2$
and among given options
$n_{2} / n_{1} = 2 / 1 = 4 / 2 = 6 / 3 = 2$