The time period of a freely suspended magnetic needle does not depend upon

length of the magnet

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pole strength

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horizontal component of earths magnetic field

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length of the suspension

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Solution

The correct option is D length of the suspension
The time period of oscillation of a bar magnet suspended in air is given by
$T = 2 π \sqrt{\frac{I}{M B_{H}}}$
It depends on , Moment of Inertia( depends on length and breadth of the magnet) , magnetic moment and earth's horizontal magnetic field.

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