The time period of a mass suspended from a spring is T. If is the spring is cut into four equal parts and the same mass is suspend from one of the parts, then the new time period will be -

T/4

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T/2

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Solution

The correct option is B T/2
$K ℓ = c o n s t a n t \Rightarrow K^{'} = 4 K$
& $T = 2 π \sqrt{\frac{m}{K}} \Rightarrow T^{'} = \frac{T}{2}$

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The time period of a mass suspended from a spring is T. If is the spring is cut into four equal parts and the same mass is suspend from one of the parts, then the new time period will be -

The correct option is B T/2Kℓ=constant⇒K′=4K& T=2π√mK⇒T′=T2

The correct option is B T/2
$K ℓ = c o n s t a n t \Rightarrow K^{'} = 4 K$
& $T = 2 π \sqrt{\frac{m}{K}} \Rightarrow T^{'} = \frac{T}{2}$