Question

The time period of a particle executing SHM is 2s. After what time interval from t = 0, will its displacement be half the amplitude:

• A. (1/4) secs
• B. (1/6) secs
• C. (1/2) secs
• D. 1 sec

Answer 1

Answer: (B)

(1/6) secs

Let $x=Asinwt$ be the equation of SHM. The value of x is given a $x=A/2$. Here $w=\frac{2\pi }{T}$

Substituting, we get $sin\omega t=1/2⟹\omega t=\pi /6$ or $t=\left(1/6\right)s$

The correct option is (b)