Question

The time period of a satellite of earth is $5$ hours. If the separation between the earth and the satellite is increased to $4$ times the previous value, the new time period will become

• A. $10hours$
• B. $80hours$
• C. $40hours$
• D. $20hours$

Answer 1

Answer: (C)

$40hours$

$T^2\propto r^3\frac{T_1}{T_2}={\left(\frac{r_1}{r_2}\right)}^{\frac{3}{2}}\Rightarrow T_2=8T_1=40hours$