Question

The time period of a simple pendulum is directly proportional to the square root of its length. State true or false.

• A. True
• B. False

Answer 1

The correct option is A True

The time period of simple pendulum can be written as

$T=2\pi \sqrt[]{\frac{l}{g}}$

$l$= length of pendulum

$g$= acceleration due to gravity at the position of simple pendulum.

Now when $g$ is unchanged and as $2\pi$ is constant, $T$ will only depend on length as the square root of it. So our given statement is true.