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Satellites

The time peri...

Question

The time period of a simple pendulum on a freely moving artificial satellite is

A

Zero

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B

2 sec

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C

3 sec

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D

Infinite

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Solution

The correct option is D
Infinite

Time period of simple pendulum $T = 2 π \sqrt{\frac{l}{g^{'}}}$
In artificial satellite $g^{'} = 0 ∴ T = i n f i n i t e .$

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