The time period of a simple pendulum on earth is 2 s. What will be the time period of same pendulum when it is brought on moon? (Value of g at moon is 1/6 of value of g at earth’s surface:

4.9 s

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6 s

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4.2 s

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4 s

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Solution

The correct option is A
4.9 s

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Similar questions

A simple pendulum has a time period exactly 2s when used in a laboratory at north pole. What will be the time period if the same pendulum is used in a laboratory at equator? Account for the earth's rotation only. Take g $\frac{G m}{r^{2}}$ = 9.8 m/s² and radius of earth = 6400 km.

Q. The acceleration due to gravity on the surface of moon is 1.7 m s¯². What is the time period of a simple pendulum on the surface of moon if its time period on the surface of earth is 3.5 s ? (g on the surface of earth is 9.8 m s¯²)

Q. The acceleration due to gravity on the surface of the moon is

1.7 m s^{- 2}

. The time period of a simple pendulum on the moon if its time period on the earth is

3.5

s is (Given,

g = 9.8 m s^{- 2})

Q. The time period of simple pendulum changes when it is taken on the moon.

Q. The time period of a simple pendulum on the surface of the earth is

4

s. Its time period on the surface of the moon is:

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The time period of a simple pendulum on earth is 2 s. What will be the time period of same pendulum when it is brought on moon? (Value of g at moon is 1/6 of value of g at earth’s surface:

The correct option is A 4.9 s

The correct option is A
4.9 s