The time period of a thin magnet is 4 s. If it is divided into two equal halves, then the time period of each part will be:

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Solution

The correct option is C 2s
In case of vibration magnetometer when a magnet is cut n equal parts by cutting normal to its length. Then the time period of each part of magnet will be
$T^{'} = \frac{T}{n}$ ...(i) (here, $T = 4 s, n = 2$ )
Now, Putting the given values in Eq. (i), we get
$T^{'} = \frac{4}{2} = 2 s$

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The time period of a thin magnet is 4 s. If it is divided into two equal halves, then the time period of each part will be:

The correct option is C 2sIn case of vibration magnetometer when a magnet is cut n equal parts by cutting normal to its length. Then the time period of each part of magnet will be T′=Tn ...(i) (here, T=4s,n=2)Now, Putting the given values in Eq. (i), we getT′=42=2s