The time period of a vibrating body is $0.01 s e c$ . Its frequency will be :

1.0 s^{- 1}

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10.0 s^{- 1}

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100.0 s^{- 1}

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1000.0 s^{- 1}

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Solution

The correct option is C $100.0 s^{- 1}$
Given,
Time period $= 0.01 s e c$
We have to find the frequency.
We have the relation, $F r e q u e n c y = \frac{1}{T i m e P e r i o d}$
$∴ F r e q u e n c y = \frac{1}{0.01} = 100 s^{- 1}$

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The Time period of a vibrating body of frequency 100 Hz is:

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