The time period of an object performing SHM is 16 s. It starts its motion from the equilibrium position. After 2 s its velocity is π m/s. What is its displacement amplitude?
A
√2 m
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B
2√2 m
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C
4√2 m
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D
8√2 m
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Solution
The correct option is D8√2 m Displacement of the object, x=A sin ωt Velocity, v=Aωcosωt Since, ω=2πT=2π16 Therefore, v=A(2π16)cos 2π16×2 π=A×2π16×1√2 Hence, A=π×162π×√2=8√2 m