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Question

the time period of Jupiter is 11.6 years how far is Jupiter from the sun distance of the earth from the sun is 1.5 into 10 ^ 11 metres

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Solution

Dear student,
$T_{p} = 11.6 y r T_{e} = 1 y r r_{e} = 1.5 \times 10^{11} T^{2} = k r^{3} \frac{{T_{p}}^{2}}{{T_{e}}^{2}} = \frac{{r^{3}}_{p}}{{r^{3}}_{e}} r_{p} = (\frac{T_{p}}{T_{e}})^{2 / 3} \times r_{e} r_{p} = (\frac{11.6}{1})^{2 / 3} \times 1.5 \times 10^{11} r_{p} = 7.68 \times 10^{11} m$

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