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Question

The time period of oscillations of a simple pendulum is 1 minute. If its length is increased by 44% then its new time period of oscillation will be

A
96 s
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B
58 s
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C
12 s
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D
72 s
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Solution

The correct option is C 12 s
We know T=2πlg
Tl1
Given data T1=1sec
T2=2
l1=l
l2=44%=100+44=144l
T1T2=l1l21T2=1144
T2=12sec

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