wiz-icon
MyQuestionIcon
MyQuestionIcon
22
You visited us 22 times! Enjoying our articles? Unlock Full Access!
Question

The time period of the simple harmonic motion represented by the equation d2xdt2+αx=0 is

A
2 πα
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
2 πα
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
2 π/α
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
2 π/α
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D 2 π/α
In a simple harmonic motion d2xdt2=ω2x where ω is the angular frequency. Comparing it with d2xdt2=αx we get ω2=α or ω=α or 2πT=α or T=2πα, Hence the correct choice is (d)

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Aftermath of SHM
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon