The time period of the spring mass system as shown in figure will be

T = 2 π \sqrt{\frac{m}{2 (k_{1} + k_{2} + k_{3})}}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

T = 2 π \sqrt{\frac{m}{2 k_{1} k_{2} k_{3}}}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

T = 2 π \sqrt{\frac{m (k, k_{2} k_{2})}{k_{1} + k_{2} + k_{3}}}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

T = 2 π \sqrt{\frac{m (k, k_{2} + k_{2} k_{3} + k_{3} k_{1})}{2 (k_{1} k_{2} k_{3})}}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $T = 2 π \sqrt{\frac{m}{2 (k_{1} + k_{2} + k_{3})}}$
$T = 2 π \sqrt{\frac{m}{k_{e g .}}}$
$\Rightarrow T = 2 π \sqrt{\frac{m}{2 (k_{1} + k_{2} + k_{3})}}$
Hence, the answer is $T = 2 π \sqrt{\frac{m}{2 (k_{1} + k_{2} + k_{3})}} .$

Suggest Corrections

Similar questions

A mass m is suspended from the two coupled springs connected in series. The force constant for springs are $K_{1}$ and $K_{2}$ . The time period of the suspended mass will be

Q. Two springs of force constants

k_{1}

and

k_{2}

are connected as shown figure. The time period of vertical oscillations of mass m is given by

Q. A disc of mass m is connected to two springs having spring constants

k_{1}

and

k_{2}

as shown in the figure. Find the time period of oscillation.

Find the time period of the oscillation of mass m in figures.

(i) $2 π \sqrt{\frac{m}{k_{1} + k_{2}}}$

(ii) $2 π \sqrt{\frac{m (k_{1} + k_{2})}{k_{1} k_{2}}}$

(iii) $2 π \sqrt{\frac{m (k_{1} - k_{2})}{k_{1} k_{2}}}$

A mass m is suspended by means of two coiled spring which have the same length in unstretched condition as in figure. Their force constant are $k_{1}$ and $k_{2}$ respectively. When set into vertical vibrations, the period will be

Join BYJU'S Learning Program

The time period of the spring mass system as shown in figure will be

The correct option is A T=2π√m2(k1+k2+k3)T=2π√mkeg.⇒T=2π√m2(k1+k2+k3)Hence, the answer is T=2π√m2(k1+k2+k3).

The correct option is A $T = 2 π \sqrt{\frac{m}{2 (k_{1} + k_{2} + k_{3})}}$
$T = 2 π \sqrt{\frac{m}{k_{e g .}}}$
$\Rightarrow T = 2 π \sqrt{\frac{m}{2 (k_{1} + k_{2} + k_{3})}}$
Hence, the answer is $T = 2 π \sqrt{\frac{m}{2 (k_{1} + k_{2} + k_{3})}} .$