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Question

The time period of the variation of potential energy of a particle executing SHM with period T is

A
T/4
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B
T
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C
2T
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D
T/2
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E
T/3
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Solution

The correct option is A T/4

Potential energy of particle executing SHM =12mω2x2

The relation between ω and T is given as: T=2πωorω=2πT

Put the value of ω in the potential energy expression as:

U=12m4π2T2x2

=2mπ2x2T2

U1T2



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