The time period of two simple pendulam at are in the ratio 2:1.what will be the ratio of their length?

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Solution

Dear Student ,
$T i m e p e r i o d, T \propto \sqrt{l} S o, \frac{T_{1}}{T_{2}} = \sqrt{\frac{l_{1}}{l_{2}}} \Rightarrow \sqrt{\frac{l_{1}}{l_{2}}} = \frac{2}{1} \Rightarrow \frac{l_{1}}{l_{2}} = \frac{4}{1} \Rightarrow l_{1} : l_{2} = 4 : 1 .$

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