Question

The time period T of a simple pendulum is related to the acceleration due to gravity g as

• A. $T\propto \sqrt{g}$
• B. $T\propto \frac{1}{\sqrt{g}}$
• C. $T\propto \frac{1}{g}$
• D. $T\propto \frac{1}{g^2}$

Answer 1

The correct option is B

$T\propto \frac{1}{\sqrt{g}}$

The time period of oscillation T of a simple pendulum is inversely proportional to the square root of the acceleration due to gravity g.

i.e.,$T\propto \frac{1}{\sqrt{g}}$ .