Question

The time required (approx.) to remove electrolytically one half from 0.2 litres of 1M $AgN{O}_3$ solution by a current of 1 amp is :

• A. 320 min
• B. 80 min
• C. 160 min
• D. 40 min

Answer 1

The correct option is C 160 min

$\therefore \text{Moles of}A{g}^{+}=0.2\times 1=0.2$ moles

$\text{Moles of}A{g}^{+}\text{consumed}=\frac{1}{2}\times 0.2=0.1$

$A{g}^{+}+e^{-}\to Ag$
1 mole Ag requires 1 mole $e^{-}$

$\therefore$ 0.1 mole Ag requires 0.1 mole $e^{-}=0.1Fcharge$

$0.1F=I\times time$

$0.1\times 96500=1\times time$

$time=\frac{0.1\times 96500}{60}min$

$=\frac{965}{6}=160min$

Hence, option C is correct.