Question

The time required for a current of 3 ampere to decompose electrolytically 18 g of $H_{2}O$ is:

• A. 18 hour
• B. 36 hour
• C. 9 hour
• D. 18 second

Answer 1

The correct option is C 9 hour

$\theta =nF$

$n\to$ No. of moles

$F\to$ Faraday's constant

$\theta \to$ charge

Moles of water $=\frac{18g}{18g/mol}=1$ mole

$\theta =F$

$\theta =I\times t$

$I=3$ amp

$t=\frac{96500}{3}$

$t=8.935\sim 9$hour