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Faraday's First Law

The time requ...

Question

The time required to coat a metal surface of $80 c m^{2}$ with $5 \times 10^{- 3} c m$ thick layer of silver (density $1.05 g / c m^{3}$ ) by passing a current of $3 a m p$ through silver nitrate solution is____________.

115 s e c

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125 s e c

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135 s e c

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145 s e c

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Solution

The correct option is B $125 s e c$
Mass of silver in coated layer $= v o l u m e \times d e n s i t y$
$= (80 \times 5 \times 10^{- 3}) \times 1.05 g$
$= 0.42 g$
$∵ W = \frac{I t E}{96500}$
$∴ t = \frac{W \times 96500}{I \times E} = \frac{0.42 \times 96500}{3 \times 108} = 125.09 s e c$ .

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