The time required to liberate one gram equivalent of an element by passing one ampere current through its solution is:

6.7

Hrs

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13.4

Hrs

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19.9

Hrs

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26.8

Hrs

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Solution

The correct option is C $26.8$ Hrs
A Faraday is defined as amount of electric charge in one mole of electrons.
$1 F = 96, 500$ coulombs

We know that : $Q (C) = I (A) \times t (s)$
Where,
$Q =$ charge $= 96, 500 C$
$I =$ current $1 A$
$t =$ time

Putting the values in the formula :
$t = \frac{96500 (C)}{1 (A)}$
$= 96500 s$
$= 26.8 h r s$

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The time required to liberate one gram equivalent of an element by passing one ampere current through its solution is:

The correct option is C 26.8 HrsA Faraday is defined as amount of electric charge in one mole of electrons.1F=96,500 coulombsWe know that : Q(C)=I(A)×t(s)Where,Q= charge =96,500CI= current 1At= timePutting the values in the formula :t=96500(C)1(A) =96500 s =26.8 hrs