The time(s) taken by a group of students to walk across their college is given in the table below. Find the average time

12.02 s e c

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39.12 s e c

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40.20 s e c

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31.90 s e c

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Solution

The correct option is D $31.90 s e c$
Answer:- Using direct method
Representing the data into frequency distribution table

time
$(x_{i})$ No. of students
$(f_{i})$ $f_{i} x_{i}$
10 1 10
20 2 40
25 5 125
30 6 180
45 7 315
$Σ f_{i} = 21$ $Σ f_{i} x_{i} = 670$
$∴ m e a n = \frac{Σ f_{i} x_{i}}{Σ f_{i}} = \frac{670}{21} = 31.90 s e c$
Average time is 31.90
B) 31.90 sec

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time $(x_{i})$	No. of students $(f_{i})$	$f_{i} x_{i}$
10	1	10
20	2	40
25	5	125
30	6	180
45	7	315
	$Σ f_{i} = 21$	$Σ f_{i} x_{i} = 670$

The time(s) taken by a group of students to walk across their college is given in the table below. Find the average time

The correct option is D 31.90secAnswer:- Using direct method Representing the data into frequency distribution table time(xi)No. of students(fi)fixi101 10 20 2 40 25 5 12530 6 18045 7 315 Σfi=21Σfixi=670∴mean=ΣfixiΣfi=67021=31.90secAverage time is 31.90B) 31.90 sec