Question

The time taken by a.c of 50 Hz in reaching from zero to maximum value is

• A. $1\times {10}^{-2}$sec
• B. $2\times {10}^{-2}$sec
• C. $50\times {10}^{-3}$sec
• D. $5\times {10}^{-3}$sec

Answer 1

The correct option is D $5\times {10}^{-3}$sec

Using $T=\frac{1}{v}=\frac{1}{50}$
For the given condition in question,
$T^{\prime }=\frac{1}{4}\times \frac{1}{50}=\frac{1}{200}=5\times {10}^{-3}$sec