The time taken by a particle performing SHM to pass from point A to B where its velocities are same is 2s. After another 2s, it returns to B.The time period of oscillation is
A
4s
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B
6s
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C
8s
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D
10s
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Solution
The correct option is B 8s We see that the velocity at A and B are same and it takes 2 s to cover this distance. Now it takes 2 s more to come back to B after travelling to the extreme position. We see that the distance covered from A to B and then from B and then back to B from extreme takes 4 s. This is half the distance in the whole top and fro path. Thus the time taken for one oscillation should be 8 s