MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Relative Position

The time take...

Question

The time taken by the ball to meet the elevator again.

Open in App

Solution

The ball will meet the elevator again when displacement of lift =
displacement of ball or $10 \times t = 40 \times t - \frac{1}{2} \times 10 \times t^{2}$ or t= 6s

Suggest Corrections

thumbs-up

0

Similar questions

Q. Time taken by the ball to reach the ground after crossing the elevator.

Q. Time when ball again meets the lift:

Q. From the top of a tower of height

40 m

, a ball is projected upwards with a speed of

20 m / s

at an angle of elevation of

30^{0}

. The ratio of the total time taken by the ball to hit the ground to its time of flight (time taken to come back to the same elevation) is :

Q. when and where the ball will meet the elevator.

Q. An elevator is goning vertically up with a constant acceleration of

2 m / s^{2}

. At the instant when its velocity is

4 m / s

a ball is projected from the floor of the elevator with a speed of

4 m / s

relative to the floor with an angular elevation of

60^{o}

. The time taken by the ball to return the floor is

(g = 10 m / s^{2})

.

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Relative Motion

PHYSICS

Watch in App

explore_more_icon

Explore more

Relative Position

Standard XII Physics

Join BYJU'S Learning Program

CrossIcon