Question

The time taken by the projectile to reach from A to B is t. Then the distance AB is equal to

• A. $\frac{ut}{\sqrt{8}}$
• B. $\frac{ut}{\sqrt{3}}$
• C. $\sqrt{8ut}$
• D. 2 ut

Answer 1

The correct option is B

$\frac{ut}{\sqrt{3}}$

$V_H=ucos{60}^{\circ }=\frac{u}{2}AC=\frac{ut}{2}AB=ACsec{30}^{\circ }=\left(\frac{ut}{2}\right)\times \frac{2}{\sqrt{3}}=\frac{ut}{\sqrt{3}}$