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Byju's Answer

Standard XII

Physics

Velocity in 2D

The time take...

Question

The time taken by two running trains in crossing each other is calculated by dividing the sum of the lengths of two trains by the total speed of the two trains if the length of the first train is L the length of the second train is $L_{2}$ the speed of the first train is $V_{1}$ and the speed of the second trains is $V_{2}$ Which of the following expressions would represent the time taken ?

{(L_{1} " L_{2})}_{1}^{*} (V_{1} " V_{2})

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(L_{1} " L_{2}) @ (V_{1}^{''} V_{2})

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[(L_{1} " L_{2}) @ (V_{1} " V_{2})] * 60

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(L_{l}^{'} L_{2}) @ (V_{1}^{'} V_{2})

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Solution

The correct option is B $(L_{1} " L_{2}) @ (V_{1}^{''} V_{2})$
Clearly time taken=sumoflengthsoftwotrainstotalspeedoftwotrains
=L1+L2V1+V2=(L1"L2)@(V1"V2)

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Similar questions

Q. The time taken by two running trains in crossing each other is calculated by dividing the sum of the lengths of two trains by the total speed of the two trains. If the length of the first train is

L_{1}

, the length of the second train is

L_{2}

, the speed of the first train is

V_{1}

and the speed of the second train is

V_{2}

, which of the following expressions would represent the time taken?

In the question given below, use the following notations

A " B

means add

B

to A

A^{'} B

means subtract

B

from

A

A @ B

means divide

A

B

A * B

means multiply

A

B

The time taken by two running trains in crossing each other is calculated by dividing the sum of the lengths of two trains by the total speed of the two trains. If the length of the first trains is

L_{1}

, the length of the second trains is

L_{2}

, the speed of the first train is

V_{1}

and the speed of the second trains is

V_{2}

, which of the following expressions would represent the time taken?

In the question given below, use the following notations :

A " B means 'add B to A';

A ' B means 'subtract B from A';

A @ B means 'divide A by B';

A ★ B means 'multiply A by B';

Now, answer the following question.

The time taken by two running trains in crossing each other is calculated by dividing the sum of the lengths of two trains by the total speed of the two trains. If the length of the first train is

L_{1}

, the length of the second train is

L_{2}

, the speed of the first train is

V_{1}

and the speed of the second train is

V_{2}

, which of the following expressions would represent the time taken ?

If two trains moving at $v_{1}$ and $v_{2}$ crosses tunnels of lengths 160 m and 100 m respectively in the same time. Find the ratio of $v_{1} : v_{2}$ .

The driver of a train moving with a constant velocity v₁along a straing track sights another train at a distance d ahrad of him on the same track moving in a same direction with a constant speed V2. He at once applies a brakes and gives his train a constant retardation f. There will be a collosioc of yhe trains if......?

a) v1 > V2 amd (V1 -V2)²/2f < d

b) V1<V2 and (V1+V2)² /2f > d

c) V1 > V2 and ( V1-V2)²/2f > d

d) V1>V2 and (V1²- V2²)/2f > d

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The correct option is B (L1"L2)@(V′′1V2)Clearly time taken=sumoflengthsoftwotrainstotalspeedoftwotrainssumoflengthsoftwotrainstotalspeedoftwotrains=L1+L2V1+V2=(L1"L2)@(V1"V2)

The correct option is B $(L_{1} " L_{2}) @ (V_{1}^{''} V_{2})$
Clearly time taken=sumoflengthsoftwotrainstotalspeedoftwotrains
=L1+L2V1+V2=(L1"L2)@(V1"V2)