Question

The time taken for a certain volume of a certain gas to diffuse through a small hole was $2min$. Under similar conditions, an equal volume of oxygen took $5.65min$ to pass. The molecular mass of gas (in amu) is:

Answer 1

Diffusion rate $\frac{r_1}{r_2}=\frac{t_2}{t_1}=\sqrt{\frac{M_2}{M_1}}=5.65/2=\sqrt{\frac{32}{x}}$
$⟹x=4$.