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Question

The time taken for a certain volume of gas to diffuse through a small hole was 2 min. Under similar conditions an equal volume of oxygen took 5.65 minute to pass. The molecular mass of the gas is:

A
32
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B
11.33
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C
4
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D
8
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Solution

The correct option is D 4
We know that
r1r2=M1M1=v1+2v2+1 v1=v2
32M=v1×5.65v1×2
32M=(2.825)2=7.98
M=327.98=4.0

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