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Question

The time variation of the position of a particle in rectilinear motion is given by x=2t3+t2+2t. If v is the velocity and a the acceleration of the particle in consistent units, the motion started with


A

v=0,a=0

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B

v=0,a=2

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C

v=2,a=0

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D

v=2,a=2

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Solution

The correct option is D

v=2,a=2


Given:
x=2t3+t2+2t

Velocity: V=dxdt=6t2+2t+2

At t=0 (start of motion)
V=0+0+2
V=2
Acceleration: a=dvdt=12t+2

At t=0
a=0+2
a=2


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