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Byju's Answer
Standard XII
Physics
Centripetal Acceleration
the time when...
Question
the time when disc stops rotating:
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Solution
d
τ
=
μ
(
d
m
)
g
⋅
r
=
μ
(
M
π
R
2
)
(
2
π
r
d
r
)
g
r
∴
τ
=
∫
R
0
d
t
=
2
μ
M
g
R
3
Angular retardation,
α
=
τ
I
(
2
μ
M
g
R
/
3
)
(
1
/
2
M
R
2
)
=
4
μ
g
3
R
0
=
ω
0
−
α
t
∴
t
=
ω
0
α
=
3
ω
0
R
4
μ
g
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