The torque on a bar magnet due to the earth's magnetic field is maximum when the axis of the magnet is

Perpendicular to the field of the earth

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Parallel to the vertical component of the earth's field

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At an angle of 30 deg with respect to the N-S direction

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Along the North-South (N-S) direction

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Solution

The correct option is A
Perpendicular to the field of the earth

.

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Similar questions

10^i A - m^{2}

¯ ¯¯ ¯ B = (2^i + 3^j) T

When a bar magnet is suspended freely in a uniform magnetic field, identify the correct statements:

a) The magnet experiences only couple and undergoes only rotatory motion

b) The direction of torque is along the suspension wire

c) The magnitude of torque is maximum when the magnet is normal to the field direction

0.1 m

5 {A m}^{2}

0.4 T

60^{o}

30^{o}

900

0.02

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