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Question

The total acceleration of a particle in circular motion is 25 ms2. If the speed of the particle decreases at a rate of 15 ms2. If radius of the path of the particle is r=2 m, the angular speed ω of the particle relative to the centre of the circle is

A
1rads
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B
10 rads
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C
2 rads
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D
210 rads
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Solution

The correct option is B 10 rads
Let the tangential acceleration be at,
centripetal acceleration be ac,
Net acceleration be a
Given,
a=25 ms2,at=15 ms2,r=2 m
a=a2t+a2ca2=a21+a2c
252=152+a2c
a2c=202ac=20

ω2r=20
ω2=202=10ω=10rads

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