The total acceleration of a particle in circular motion is 5m/s2. If the speed of the particle decreases at a rate of 3m/s2, assuming r=2m, the angular speed ω of the particle relative to the centre of the circle is
A
1rad/s
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
√2rad/s
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
2rad/s
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
2√2rad/s
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is B√2rad/s Let the tangential acceleration be at and centripetal acceleration be ac Given, a=5m/s2,at=3m/s2,r=2ma=√a2t+a2c⇒a2=a2t+a2c⇒52=32+a2c ∴ac=4m/s2