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Standard XII

Physics

Mechanism of Nuclear Fission

The total bin...

Question

The total binding energy of an a particle $(_{2} H e_{4})$ is $24.4 MeV$ whereas the total binding energy of a deuteron $(_{1} H^{2})$ is $2.2 MeV$ When two deuterons are made to combine

An amount of

22.2 MeV

energy will be released

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An amount of

20.0 MeV

energy will be released

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An amount of

20.0 MeV

energy will be consumed

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An amount of

22.2 MeV

energy will be consumed

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Solution

The correct option is B An amount of $20.0 MeV$ energy will be released
$Q = 24.4 - 2 \times 2.2 = 20 MeV$

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The total binding energy of an a particle (2He4) is 24.4 MeV whereas the total binding energy of a deuteron (1H2) is 2.2 MeV When two deuterons are made to combine

The correct option is B An amount of 20.0 MeV energy will be releasedQ=24.4−2×2.2=20 MeV

The total binding energy of an a particle $(_{2} H e_{4})$ is $24.4 MeV$ whereas the total binding energy of a deuteron $(_{1} H^{2})$ is $2.2 MeV$ When two deuterons are made to combine

The correct option is B An amount of $20.0 MeV$ energy will be released
$Q = 24.4 - 2 \times 2.2 = 20 MeV$