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Question

The total charge required for the oxidation of two moles of Mn3O4 into MnO2−4 ions in an alkaline medium is:

A
5 F
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B
10 F
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C
20 F
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D
None of these
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Solution

The correct option is C 20 F
To calculate charge required for oxidation,
first we need to balance the equation
as the reaction is in alkaline medium change in oxidation state of Mn = +83 to +6
Mn3O43MnO24+10e for balancing O we will add OH
Mn3O4+16OH3MnO24+8H2O+10e
For 1 mole 10e are required so for 2 mole 20e are required.

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