The total current supplied to the circuit by the battery is
4 A
The equivalent circuit is shown in the figure.
Net resistance in the upper arm =1.5+2×62+6=1.5+1.5=3 Ω
Now we have 3 Ω and 3 Ω resistance is parallel. The net resistance is R=3×33+3=1.5 Ω
Current, I=6 V1.5 Ω=4 A