The total energy of a hydrogen atom in its ground state is −13.6eV. If the potential energy in the first excited state is taken as zero then the total energy in the ground state will be:
A
−3.4eV
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B
3.4eV
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C
−6.8eV
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D
6.8eV
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Solution
The correct option is C−6.8eV Total energy of Hydrogen atom in ground state is −13.6eV ,and potential energy is −27.2ev, Kinetic energy =13.6eV
For first excited state Kinetic energy = 3.4eV, Potential energy= −6.8eV,
If potential energy of first excited energy is zero , Then for this we must add 6.8eV energy in system . We are just shifting the potential refrence.
So for ground state total energy =(13.6−27.2+6.8)=−6.8eV