The total energy of a hydrogen atom in its ground state is −13.6eV. If the potential energy in the first excited state is taken as zero then the total energy in that state will be
A
−3.4eV
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B
3.4eV
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C
−6.8eV
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D
6.8eV
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Solution
The correct option is A−3.4eV E=Ep+Ek=−2Ek+EkE=−EkEk=−(−13.6)22=13.64=3.4evE=−Ek=−3.4ev