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Question

The total energy of a particle performing SHM is E. What will be the kinetic energy of the particle, when displacement is half of the amplitude?

A
32E
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B
E2
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C
3E4
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D
E3
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Solution

The correct option is C 3E4
Kinetic energy of particle executing SHM is given by
KE=12mv2
v=ωA2y2
KE=12mω2(A2y2)
When y=A2
KE=12mω2(A2(A2)2)
=12mω2(3A24)
=34(12mω2A2)
Total energy of particle executing SHM is (E)=12mω2A2
KE=3E4
Hence, option (c) is correct.

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