The total energy of a particle performing SHM is E. What will be the kinetic energy of the particle, when displacement is half of the amplitude?
A
√32E
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B
E2
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C
3E4
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D
E3
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Solution
The correct option is C3E4 Kinetic energy of particle executing SHM is given by KE=12mv2 ∵v=ω√A2−y2 KE=12mω2(A2−y2)
When y=A2 KE=12mω2(A2−(A2)2) =12mω2(3A24) =34(12mω2A2)
Total energy of particle executing SHM is (E)=12mω2A2 ∴KE=3E4
Hence, option (c) is correct.