The total energy of an electron in the first excited state of hydrogen is about -3.4 eV. Its kinetic energy in this state is

3.4 eV

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6.8 eV

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-3.4 eV

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-6.8 eV

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Solution

The correct option is A
3.4 eV

$K E = - T E = 3.4 e V$

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The total energy of an electron in the first excited state of the hydrogen atom is about -3.4 eV. What is the kinetic energy and potential energy of the electron in this state?

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The total energy of an electron in the first excited state of hydrogen is about -3.4 eV. Its kinetic energy in this state is

The correct option is A 3.4 eV KE=−TE=3.4 eV

The correct option is A
3.4 eV

$K E = - T E = 3.4 e V$