The total energy of electron in the ground state of hydrogen atom is 13.6 eV. The kinetic energy of an electron in the first excited state is :

1.7 e V

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3.4 e V

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6.8 e V

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13.6 e V

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Solution

The correct option is B $3.4 e V$
Total energy in first excited state $= - \frac{13.4}{4} = - 3.4 e V$ .
K.E. in first excited state $=$ total energy in that state $= (3.4) = 3.4 e V$

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The total energy of an electron in the first excited state of hydrogen is about -3.4 eV. Its kinetic energy in this state is

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