The total energy of electron in the second excited state is $- 2$ E. What is its potential energy in the same state with proper sign $?$

- 2 E

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- 4 E

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4 E

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- E

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Solution

The correct option is B $- 4 E$
Potential energy of electron
$E = E_{i} - E_{f}$

Hence $- 2 E + x = 2 E$
$x = 4 E$
$x = - 4 E$ .

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The total energy of electron in the second excited state is −2E. What is its potential energy in the same state with proper sign?

The correct option is B −4EPotential energy of electronE=Ei−EfHence −2E+x=2Ex=4Ex=−4E.

The total energy of electron in the second excited state is $- 2$ E. What is its potential energy in the same state with proper sign $?$

The correct option is B $- 4 E$
Potential energy of electron
$E = E_{i} - E_{f}$

Hence $- 2 E + x = 2 E$
$x = 4 E$
$x = - 4 E$ .