Question

The total energy of one mole of an ideal monatomic gas at ${27}^{o}C$ is ($X\times$ 100) cal. The value of $X$ is ____.

Answer 1

The expression for the total energy is $E=\frac{3}{2}RT$

Substituting values in the above expression:
At ${27}^{o}C,E=\frac{3}{2}RT$

$=\frac{3}{2}\times 2cal/K/mol\times 300K$

$=900cal/mol$

Hence, the total energy of one mole of an ideal monoatomic gas at ${27}^{o}C$ is $900$ $cal$.