Question

The total energy of one mole of an ideal monoatomic gas at ${27}^{o}C$ is ______(in $cal$).

Answer 1

The energy of one mole of an ideal monoatomic gas = $\frac{3}{2}RT$

$R=8.314J{K}^{-1}mo{l}^{-1}=2cal{K}^{-1}mo{l}^{-1}$

$E=\frac{3}{2}\times 2\times 300=900cal$